The Limited Times

Now you can see non-English news...

The card trick - puzzle of the week

2022-08-14T05:45:43.739Z

30 playing cards are spread over three piles. Three different colors appear ten times each. How many times do you have to swap cards until each deck contains only cards of the same suit?



Photo:

THE MIRROR

There are 30 playing cards on a table.

They have three different colors that appear equally often.

So there are ten of each color.

Three stacks of ten cards each are randomly formed from the 30 colors - see drawing above.

You should now rearrange the cards so that only cards of the same suit are left in each of the three stacks.

A reshuffling step works like this: you take a card from one deck and swap it with a card from another deck.

What is the maximum number of such steps required until each stack is one color?

We are looking for the smallest number of steps with which sorting by color works in all constellations.

Cards must be exchanged a

maximum of ten times

.

First, a general consideration: in every ten-card deck, there is at least one suit that appears four or more times in it.

Why is that?

If each of the three colors were present a maximum of three times in a stack, there would not be a total of ten cards.

We now make a case distinction and start with the simple case:

A color occurs five or more times in a stack

.

Then we have to swap at most five cards until all ten cards in this deck are the same suit.

Two stacks remain, in which only the other two colors appear.

In the worst case, both colors appear five times in both stacks.

We therefore need a maximum of five more steps until these two stacks are also one color.

A maximum of ten steps

are therefore necessary

in total .

Now for the second case:

The maximum number of cards of one suit in all three piles is four.

In any case, we then have to

swap six cards

until the first stack is one color.

If the remaining two colors appear five times each in the two other stacks, five more steps would be necessary, for a total of eleven.

But we can prevent this constellation, as we shall see shortly.

In some cases, we even only need nine steps in total.

We look at the three possible color distributions:

  • In all three stacks, one suit is quadruple and two suits are triple.

  • In all three stacks, two suits are quadruple and one suit is double.

  • The constellation fourfold, fourfold, twofold occurs in only one stack - in the other two stacks it is fourfold, threefold, threefold.

  • In

    distribution 1

    we only need nine steps until all three stacks are one color - see the following sketch:

    Distribution 2

    requires ten steps.

    There are several options, one of which is shown here:

    In

    distribution 3

    , we can also sort the colors in only ten steps.

    A variant of the solution is shown in the following drawing.

    With this we proved that we need at most ten steps to sort the stacks by color.

    I discovered this riddle on Twitter from Australian James Stanton's account.

    In case you missed a mystery from the past few weeks, here are the most recent episodes:

    • How many elevators are needed?

    • Rook versus bishop

    • Beetles in love

    • John Conway's super number

    • Bizarre arithmetic

    • Miraculous handshake

    • Paul wins too often

    • How long is the red line?

    • Does a cube fit through itself?

    • The monster number and its two non-divisors

    Source: spiegel

    All business articles on 2022-08-14

    You may like

    Business 2022-09-11T16:38:10.130Z
    Business 2022-09-25T05:40:18.738Z
    Business 2022-09-18T05:01:24.516Z
    Business 2022-08-21T05:06:28.967Z
    Life/Entertain 2022-07-08T15:30:07.775Z

    Trends 24h

    Business 2022-09-26T10:29:03.027Z

    Latest

    © Communities 2019 - Privacy