Washington-Sana
Belarusian Victoria Azarenka qualified for the fourth round of the Indian Wells Open.
Sky Sports reported that Azarenka qualified for the fourth round after beating Czech Petra Kvitova 7-5, 6-4, in a time of one hour and 49 minutes.
In the fourth round, Azarenka will face compatriot Alexandra Sasnovich.
Elina Svitolina also qualified for the quarter-finals of the tournament.
And "Sky Sports" network said that Svitolina climbed to the final price of the tournament after defeating Romanian Christina in two sets against a group by 6-4, 4-6, 6-7 in a time of two and a half hours.
Poland's Iga Šviontik was the first to reach the final, by defeating Kudermetova in two sets, 1-6, 0-6, in a time that did not exceed two hours.